4x=4x^2+8x-1

Solution for 4x=4x^2+8x-1 equation:

4x=4x^2+8x-1

We move all terms to the left:

4x-(4x^2+8x-1)=0

We get rid of parentheses

-4x^2+4x-8x+1=0

We add all the numbers together, and all the variables

-4x^2-4x+1=0

a = -4; b = -4; c = +1;
Δ = b2-4ac
Δ = -42-4·(-4)·1
Δ = 32
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{32}=\sqrt{16*2}=\sqrt{16}*\sqrt{2}=4\sqrt{2}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-4\sqrt{2}}{2*-4}=\frac{4-4\sqrt{2}}{-8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+4\sqrt{2}}{2*-4}=\frac{4+4\sqrt{2}}{-8}
$